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List of ngos in africa, Why is the output of the following two list comprehensions different, even though f and the lambda function are the same?. timeit () or preferably timeit. Nov 2, 2010 · When reading, list is a reference to the original list, and list[:] shallow-copies the list. Try it yourself with timeit. repeat (). Why is the output of the following two list comprehensions different, even though f and the lambda function are the same? I have a piece of code here that is supposed to return the least common element in a list of elements, ordered by commonality: def getSingle(arr): from collections import Counter c = Counte Oct 5, 2012 · By using a : colon in the list index, you are asking for a slice, which is always another list. Other than that I think the only difference is speed: it looks like it's a little faster the first way. I have a piece of code here that is supposed to return the least common element in a list of elements, ordered by commonality: def getSingle(arr): from collections import Counter c = Counte Oct 5, 2012 · By using a : colon in the list index, you are asking for a slice, which is always another list. The notation List<?> means "a list of something (but I'm not saying what)". When assigning, list (re)binds the name and list[:] slice-assigns, replacing what was previously in the list. : represents going through the list -1 implies the last element of the list Official Google Search Help Center where you can find tips and tutorials on using Google Search and other answers to frequently asked questions. In Python you can assign values to both an individual item in a list, and to a slice of the list. See Flatten an irregular (arbitrarily nested) list of lists for solutions that Closed 1 year ago. Using a type parameter (like in your point 3), requires that the type parameter be declared. This is exactly analogous to declaring formal parameter Mar 20, 2013 · It gets all the elements from the list (or characters from a string) but the last element. The most popular solutions here generally only flatten one "level" of the nested list. The second, list(), is using the actual list type constructor to create a new list which has contents equal to the first list. The first, [:], is creating a slice (normally often used for getting just part of a list), which happens to contain the entire list, and thus is effectively a copy of the list. The Java syntax for that is to put <T> in front of the function. The first way works for a list or a string; the second way only works for a list, because slice assignment isn't allowed for strings. Since the code in test works for any kind of object in the list, this works as a formal method parameter. Also, don't use list as a name since it shadows the built-in. If your list of lists comes from a nested list comprehension, the problem can be solved more simply/directly by fixing the comprehension; please see How can I get a flat result from a list comprehension instead of a nested list?.
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